2000 - WAEC Mathematics Past Questions and Answers - page 3

P(Kodjo passing) = \(\frac{3}{4}\); P(Adoga passing) = \(\frac{3}{5}\)

P(Kodjo failing) = \(\frac{1}{4}\); P(Adoga failing) = \(\frac{2}{5}\)

P(both fail) = \(\frac{1}{4} \times \frac{2}{5}\)

= \(\frac{1}{10}\)

< Q = < R (OQ = OR = radii)

< QOR = 180° - 2(40°) = 100°

< QSR = < RPQ = \(\frac{1}{2}\) < QOR

= \(\frac{100}{2} = 50°\)

Interior angle = 2(75°)

= 150°

Sum of interior angle in a hexagon = (6 - 2) x 180°

= 720°

\(\therefore\) 107° + 2x° + 150° + 95° + (2x - 15)° + 123° = 720°

460 + 4x = 720 \(\implies\) 4x = 720 - 460

4x = 260° \(\implies\) x = 65°

< T = < S = 50° (OS = OT)

< SOT = 180° - 2(50°) = 80°

< ROP = 80° (vertically opposite angle)

\(\therefore\) < OPQ = 180° - 80° = 100° (adjacent angles)

\(x = -\frac{1}{2}, y = 4\
3x^2y + xy^2\
3\left[-\frac{1}{2}\right]^2 \times 4 \times + \left(\frac{-1}{2}\right)(4)^2\
3\times \frac{1}{4} \times 4 -\frac{1}{2} \times 16\
3-8 = -5\)

\(x \propto \frac{1}{y}\)

\(x = \frac{k}{y}\)

\(\frac{2}{3} = \frac{k}{9}\)

\(3k = 18 \implies k = 6\)

\(x = \frac{6}{y}\)

When y = \(\frac{3}{4}\),

x = \(\frac{6}{\frac{3}{4}}\)

= \(\frac{6 \times 4}{3}\)

= 8

\(2x^2 + 3x - 14\)

\(2x^2 + 7x - 4x - 14\)

\(x(2x + 7) - 2(2x + 7)\)

= \((x - 2)(2x + 7)\)

The other factor = (x - 2).