Question on: WAEC Mathematics - 2000
In the diagram, POS and ROT are straight lines, OPQR is a parallelogram. |OS| = |OT| and ∠OST = 50°. Calculate ∠OPQ.
A
160o
B
140o
C
120o
D
100o
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Correct Option: D
< T = < S = 50° (OS = OT)
< SOT = 180° - 2(50°) = 80°
< ROP = 80° (vertically opposite angle)
\(\therefore\) < OPQ = 180° - 80° = 100° (adjacent angles)
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