Question on: JAMB Physics - 1994
When 100g of liquids L1 at 78oC was mixed with Xg of liquid L2 at 50oC, the final temperature was 60oC. Given that the specific heat capacity of L2is half that of L1, find x
A
50g
B
100g
C
150g
D
200g
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Correct Option: C
Heat lost by L1 = heat gained by L2
cL1 = 2cL2
100 x 2cL2 x (78 - 60)
= xg x cL2 x (60 - 50)
xg = 150g
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