Question on: JAMB Mathematics - 1994
What is the value of sin(-690)?
A
\(\frac{\sqrt{3}}{2}\)
B
-\(\frac{\sqrt{3}}{2}\)
C
\(\frac{-1}{2}\)
D
\(\frac{1}{2}\)
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Correct Option: D
Sin(-690o) = Sin(-360 -3300
sin - 360 = sin 0
∴ sin(-690o) = sin(330o)
Negative angles are measured in clockwise direction
The acute angle equivalent of sin(-330o) = sin(30o)
sin(-330o) = sin(30o)
= (\frac{1}{2})
= 0.5
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