Question on: JAMB Physics - 2024
Using the diagram above, the effective force pushing it forward at an angle 60º is
A
25.00N
B
28.87N
C
38.50N
D
43.30N
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Correct Option: A
To find the effective force pushing the object forward, we need to calculate the horizontal component of the applied force. Assuming the applied force is 50 N, the horizontal component (the effective force) can be calculated using the cosine function:
- Identify the relevant formula: Horizontal component = Force * cos(angle)
- Plug in the values: Horizontal component = 50 N * cos(60º)
- Calculate: cos(60º) = 0.5, therefore Horizontal component = 50 N * 0.5 = 25 N.
- Alternative formula: Vertical component = Force * sin(angle). Horizontal component = 50 * sin(60) = 50 * 0.866 = 43.30 N.
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