Question on: JAMB Physics - 1997
Under constant tension and constant mass per unit length, the note produced by a plucked string is 500Hz when the length of the string is 0.90m. At what length is the frequency 150Hz?
A
3m
B
4m
C
5m
D
6m
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Correct Option: A
F = (\frac{1}{2L})(\sqrt\frac{T}{m})
F1L1 = F2L2
500 x 0.9 = 150 x L2
therefore, L2 = 3m
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