Question on: SS2 Physics - Electricity and Magnetism
Two point charges, +3 μC and -5 μC, are placed 10 cm apart. What is the magnitude of the electric field at a point that is 5 cm from the positive charge?
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To calculate the electric field, we can use Coulomb's law:
Electric field (E) = (k x |q|) / r2, where k is the electrostatic constant, q is the charge, and r is the distance.
Substituting the values, we have:
E = (9 x 109 Nm2/C2 x 3 x 10-6 C) / (0.05 m).
E ≈ 1.08 x 105 N/C
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