Question on: JAMB Physics - 2019
Three resistors with resistance 200Ω, 500Ω and 1kΩ are connected in series. A 6v battery is connected to either end of the combination. Calculate the potential difference between the ends of 200Ω resistance.
A
0.71V
B
0.7V
C
0.82V
D
0.8V
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Correct Option: A
Req = 200 + 500 + 1000 = 1700Ω
| The potential difference, p.d | (across | 200Ω) | = | 200
1700 | × | 6 | = | 0.71V |
pd = 0.71v
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