Question on: WAEC Mathematics - 2007
The table shows the ages(in years) of twenty children chosen at random from a community. What is the median of the distribution? \(\begin{array}{c|c} Age(years) & 1 & 2 & 3 & 4 & 5 \ \hline {\text {Number of children}} & 2 & 3 & 5 & 6 & 4 \end{array}\)
A
3.5 years
B
3.0 years
C
2.5 years
D
2.0 years
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Correct Option: A
Median = (\(\frac{n + 1}{2})^{th}\)
= \(\frac{20 + 1}{2} = \frac{21}{2}\)
= 10.5
= \(\frac{{\text{10th term and 11th term}}}{2}\)
= \(\frac{3 + 4}{2} = \frac{7}{2}\)
= 3.5yrs
= \(\frac{20 + 1}{2} = \frac{21}{2}\)
= 10.5
= \(\frac{{\text{10th term and 11th term}}}{2}\)
= \(\frac{3 + 4}{2} = \frac{7}{2}\)
= 3.5yrs
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