Question on: JAMB Physics - 2024
The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.
A
4ms\(^{-1}\)
B
3ms\(^{-1}\)
C
2ms\(^{-1}\)
D
1ms\(^{-1}\)
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Correct Option: D
Here's how to solve the problem:
- Identify the given information:
- Wavelength (λ) = 0.25 m (distance between successive crests)
- Frequency (f) = 4 Hz (4 oscillations per second) - Recall the wave speed formula:
- v = fλ, where:
v = wave speed
f = frequency
λ = wavelength - Substitute the values and calculate:
- v = 4 Hz * 0.25 m
- v = 1 m/s
Therefore, the speed of the wave is 1 m/s.
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