Question on: JAMB Physics - 2019
The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
A
0.05kg
B
0.20kg
C
0.80kg
D
1.00kg
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Correct Option: A
M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 × 10
| M\(_r\) | = | 2
40 | = | 0.05kg |
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