Question on: JAMB Physics - 2024
The charge of magnitude 1.6 x 10 \(^{-19}\)C is placed in a uniform electric field of intensity 1200Vm\(^{-1}\). Calculate its acceleration, if the mass of the charge is 9.1 x 10\(^{-31}\)kg
A
2.11 x 10\(^{14}\)ms\(^{-2}\)
B
2.11 x 10\(^{13}\)ms\(^{-2}\)
C
1.20 x 10\(^{14}\)ms\(^{-2}\)
D
1.20 x 10\(^{13}\)ms\(^{-2}\)
Ask EduPadi AI for a detailed answer
Correct Option: A
Here's how to solve the problem:
- Calculate the electric force (F):
- The force on a charge in an electric field is given by: F = qE
- Where:
q = charge = 1.6 x 10⁻¹⁹ C
E = electric field intensity = 1200 V/m
- F = (1.6 x 10⁻¹⁹ C) * (1200 V/m) = 1.92 x 10⁻¹⁶ N - Calculate the acceleration (a):
- Using Newton's second law (F = ma), solve for acceleration: a = F/m
- Where:
F = force = 1.92 x 10⁻¹⁶ N
m = mass = 9.1 x 10⁻³¹ kg
- a = (1.92 x 10⁻¹⁶ N) / (9.1 x 10⁻³¹ kg) = 2.11 x 10¹⁴ m/s²
Therefore, the acceleration of the charge is 2.11 x 10¹⁴ m/s².
Add your answer
Please share this, thanks!
No responses