Question on: WAEC Mathematics - 2000
Simplify (\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9})
A
\(\frac{x-1}{x-3}\)
B
\(\frac{-2}{x+3}\)
C
\(\frac{x-1}{x+3}\)
D
\(\frac{4x}{x^2-9}\)
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Correct Option: B
(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}<br /> \frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}<br /> \frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}<br /> \frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3})
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