Question on: JAMB Mathematics - 1992
Resolve (\frac{3}{x^2 + x - 2}) into partial fractions
A
\(\frac{1}{x - 1} + \frac{1}{x + 2}\)
B
\(\frac{1}{x + 1} + \frac{1}{x - 2}\)
C
\(\frac{1}{x + 1} - \frac{1}{x - 2}\)
D
\(\frac{1}{x - 2} + \frac{1}{x + 2}\)
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Correct Option: A
(\frac{3}{x^2 + x - 2}) = (\frac{3}{(x - 1)(x + 1)})
(\frac{A}{x - 1}) + (\frac{B}{x + 2})
A(x + 2) + B(x - 1) = 3
when x = 1, 3A = 3 (\to) a = 1
when x = -2, -3B = 3 (\to) B = -1
3 = 1 - 1
= (\frac{1}{x - 1} + \frac{1}{x + 2})
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