Question on: JAMB Mathematics - 2014

In the diagram above, (\alpha) = 54^o(alternate angles; KL||MN) < KNM = 2(\alpha) (LN is bisector of < KNM) = 108^o

35^o + < KMN + 108^o = 180^o(sum of angles of (\bigtriangleup))

< KMN + 143^o = 180^o

< KMN = 180^o - 143^o

= 37^o