Question on: WAEC Mathematics - 2010
In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y
A
105o
B
110o
C
130o
D
150o
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Correct Option: A
In \(\bigtriangleup\) PQR,
Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 - 75
y = 105o
Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 - 75
y = 105o
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