Question on: JAMB Physics - 2011
In an A.C circuit, the ratio of r.m.s value to peak value of current is
A
2
B
\( \frac{1}{2} \)
C
\( \frac{1}{\sqrt{2}} \)
D
\( \sqrt{2} \)
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Correct Option: C
Irms = ( \frac{I_0}{\sqrt{2}} )
( \text{Therefore } \sqrt{2Irms} = I_0 \
\frac{Irms}{I_0} = \frac{1}{\sqrt{2}} )
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