Question on: JAMB Mathematics - 2024
In a committee of 5, which must be selected from 4 males and 3 females. In how many ways can the members be chosen if it were to include 2 females?
A
144 ways
B
15 ways
C
185 ways
D
12 ways
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Correct Option: D
For the committee to include 2 females, we must select 3 males so that the total number of members is 5.
Number of ways = \(^4C_3 \times ^3C_2\)
= \(\frac{4!}{(4-3)! 3!} \times \frac{3!}{(3-2)! 2!} \)
= 4 x 3
= 12 ways
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