Question on: WAEC Mathematics - 2005
If (y \alpha \frac{1}{x^2}) and (y = 1\frac{1}{4}) when x = 4, find the value of y when (x = \frac{1}{2})
A
\(2\frac{1}{2}\)
B
5
C
10
D
80
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Correct Option: D
(y \propto \frac{1}{x^2} \Rightarrow y = \frac{k}{x^2} \Rightarrow k = yx^2<br /> k = 1\frac{1}{4} \times 4^2 \Rightarrow k=\frac{5}{4}\times \frac{16}{1}=20<br /> ∴y = 20 \div \left(\frac{1}{2}\right)^2=20\times \frac{4}{1}=80)
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