Question on: JAMB Mathematics - 2008
If p varies inverse as the square of q and p = 8 when q =4, find q when p = 32
A
\(\pm\)16
B
\(\pm\)8
C
\(\pm\)4
D
\(\pm\)2
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Correct Option: D
P \(\alpha\) \(\frac{1}{q^2}\)
p = \(\frac{k}{q^2}\)
k = pq2
k = 8 x 42
k = 8 x 16 = 128
find k = pq2
q2 = \(\frac{k}{p}\)
q = \(\frac{k}{p}\)
q = \(\frac{128}{32}\)
q = √4
q = \(\pm\)2
p = \(\frac{k}{q^2}\)
k = pq2
k = 8 x 42
k = 8 x 16 = 128
find k = pq2
q2 = \(\frac{k}{p}\)
q = \(\frac{k}{p}\)
q = \(\frac{128}{32}\)
q = √4
q = \(\pm\)2
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