Question on: WAEC Mathematics - 2015
If (\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1), find the value of x.
A
1
B
\(\frac{1}{2}\)
C
-\(\frac{1}{2}\)
D
-1
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Correct Option: B
(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1)
(\frac{3^{3x} \times 3^{1 - x}}{3^{2(2 - x)}} = 3^0)
(3^{3x} \times 3^{1 - x} \div 3^{4x} = 3^0)
(3^{(3x + 1 - x - 4x)} = 3^0)
(3^{(1 - 2x)} = 3^0)
since the bases are equal,
1 - 2x = 0
- 2x = -1
x = (\frac{1}{2})
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