Question on: JAMB Mathematics - 2024
If 2x + y = 16 and 4x - y = 1/32, find the values of x and y.
A
x = 3/4, y = 11/4
B
x = 3/4, y = 13/4
C
x = 2/3, y = 4/5
D
x = 2/3, y = 13/4
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Correct Option: B
2x+y = 2⁴ ⇒ x + y = 4 ... (1)
4x-y = 2²x-y = 2²(x-y) = 2⁻⁵ ⇒ 2x - 2y = -5 ... (2)
Solving (1) and (2) simultaneously gives x = 3/4 and y = 13/4
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