Question on: SS2 Mathematics - Sequence and Series
If \(2^{n - 1}\) is the \(n\)th term of a GP. Write out the first three terms of the sequence.
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\[T_{n} = 2^{n - 1}\]
\[T_{1} = 2^{1 - 1} = 2^{0} = 1\]
\[T_{2} = 2^{2 - 1} = 2^{1} = 2\]
\[T_{3} = 2^{3 - 1} = 2^{2} = 4\]
The first three term of this GP are \(1,\ 2\ and\ 4\)
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