Question on: JAMB Physics - 2008

Given the inductor of inductance 5mH, 10mH and 20mH connected in series, the effective inductance is
A
0.35mH
B
3.50mH
C
2.90mH
D
35.0mH
Ask EduPadi AI for a detailed answer
Correct Option: D

Left = L1 + L2 + L3

= 5mH + 10mH + 20mH = 35mH

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