Question on: WAEC Mathematics - 2001
Given that sin (P = \frac{5}{13}), where p is acute, find the value of cos p - tan p
A
\(\frac{79}{156}\)
B
\(\frac{85}{156}\)
C
\(\frac{7}{13}\)
D
\(\frac{8}{1}\)
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Correct Option: A
If (sin P = \frac{5}{13}) from right angled triangle from pythagoras theorem
(BC^2 = 13^2 - 5^2<br />
=169-25<br />
BC = \sqrt{144} = 12<br />
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}<br />
=\frac{79}{156})
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