Question on: WAEC Mathematics - 2014
Given that cos x = (\frac{12}{13}), evaluate (\frac{1 - \tan x}{\tan x})
A
\(\frac{5}{13}\)
B
\(\frac{5}{7}\)
C
\(\frac{7}{5}\)
D
\(\frac{13}{5}\)
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Correct Option: C
cos x(\frac{12}{13})
132 = 122 + a2
169 = 144 + a2
a2 = 169 - 144
a2 = 25
a (\sqrt{25})
a = 5
tan x = (\frac{5}{12})
(\frac{1 - \tan x}{\tan x} = \frac{1 - \frac{5}{12}}{\frac{5}{12}})
(\frac{\frac{1 - \frac{5}{12}}{12 - 5}}{12} = \frac{\frac{7}{12}}{\frac{5}{12}})
= (\frac{7}{2} \div \frac{5}{12})
= (\frac{7}{12} \times \frac{12}{5} = \frac{7}{5})
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