Question on: JAMB Mathematics - 2024
For what range of values of x is \(\frac{1}{2}x\) + \(\frac{1}{4}\) > \(\frac{1}{3}x\) + \(\frac{1}{2}\)?
A
x < \(\frac{3}{2}\)
B
x > \(\frac{3}{2}\)
C
x < -\(\frac{3}{2}\)
D
x > -\(\frac{3}{2}\)
Ask EduPadi AI for a detailed answer
Correct Option: B
Start with:
\[ \frac{1}{2}x + \frac{1}{4} > \frac{1}{3}x + \frac{1}{2} \]
Multiply all terms by 12:
\[ 6x + 3 > 4x + 6 \]
Simplify:
\[ 2x > 3 \]
\[ x > \frac{3}{2} \]
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