Question on: JAMB Mathematics - 1992
Find the sum to infinity to the following series 3 + 2 + (\frac{4}{3}) + (\frac{8}{9}) + (\frac{16}{17}) + .....
A
1270
B
190
C
18
D
9
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Correct Option: D
3 + 2 + (\frac{4}{3}) + (\frac{8}{9}) + (\frac{16}{17}) + .....
a = 3
r = (\frac{2}{3})
s (\alpha) = (\frac{a}{1 - r}) = (\frac{3}{1 - \frac{2}{3}})
= (\frac{3}{\frac{1}{3}})
= 3 x 3
= 9
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