Question on: JAMB Mathematics - 2001

Find the number of ways of selecting 8 subjects from 12 subjects for an examination

A
490
B
495
C
496
D
498
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Correct Option: B

Combination is the number (n) of ways of selecting a number of (m) of objects from n

(^{12}C_{8}\frac{12!}{8!(12-8)!}=\frac{12!}{8!4!}\frac{(12\times 11\times 10\times 9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1)}{8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}\After\hspace{1mm} cancelling \hspace{1mm}out \hspace{1mm}we\hspace{1mm} have\11\times 5\times 9 = 495 )

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