Question on: JAMB Mathematics - 2008
Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
A
\(\frac{2}{3}\)
B
-\(\frac{2}{3}\)
C
-\(\frac{3}{2}\)
D
\(\frac{4}{3}\)
Ask EduPadi AI for a detailed answer
Correct Option: C
3x + 2y + 1 = 0
y = mx + c
2y = -3x - 1
y = -\(\frac{3}{2}\) x -\(\frac{1}{2}\)
m = -\(\frac{3}{2}\)
y = mx + c
2y = -3x - 1
y = -\(\frac{3}{2}\) x -\(\frac{1}{2}\)
m = -\(\frac{3}{2}\)
Add your answer
Please share this, thanks!
No responses