Question on: JAMB Mathematics - 2008
Evaluate \(\frac{\frac{3}{8} \div \frac {1}{2} - \frac{1}{3}}{\frac{1}{8} \times \frac {2}{3} + \frac{1}{3}}\)
A
\(\frac{1}{4}\)
B
\(\frac{1}{3}\)
C
\(\frac{1}{2}\)
D
1
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Correct Option: D
\(\frac{\frac{3}{8} \div \frac {1}{2} - \frac{1}{3}}{\frac{1}{8} \times \frac {2}{3} + \frac{1}{3}}\)
= \(\frac{\frac{3}{8} \times \frac {2}{1} - \frac{1}{3}}{\frac{1}{8} \times \frac {2}{3} + \frac{1}{3}}\)
= \(\frac{\frac{6}{8} - \frac{1}{3}}{\frac{2}{24} + \frac{1}{3}}\)
= \(\frac{\frac {18 - 8}{24}}{\frac{2 + 8}{24}}\) = \(\frac{\frac{10}{24}}{\frac{10}{24}}\)
= \(\frac{10}{24}\) \(\div\) \(\frac{10}{24}\)
= \(\frac{10}{24}\) x \(\frac{24}{10}\) = 1
= \(\frac{\frac{3}{8} \times \frac {2}{1} - \frac{1}{3}}{\frac{1}{8} \times \frac {2}{3} + \frac{1}{3}}\)
= \(\frac{\frac{6}{8} - \frac{1}{3}}{\frac{2}{24} + \frac{1}{3}}\)
= \(\frac{\frac {18 - 8}{24}}{\frac{2 + 8}{24}}\) = \(\frac{\frac{10}{24}}{\frac{10}{24}}\)
= \(\frac{10}{24}\) \(\div\) \(\frac{10}{24}\)
= \(\frac{10}{24}\) x \(\frac{24}{10}\) = 1
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