Question on: JAMB Physics - 2024
Calculate the quantity of heat for a copper rod whose thermal capacity is 400 J/K for a temperature change of 60ºC to 80ºC
A
2KJ
B
4KJ
C
6KJ
D
8KJ
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Correct Option: D
Given thermal capacity C = 400 J/K, temperature change ΔT = 80ºC - 60ºC = 20 K.
Quantity of heat: Q = C * ΔT = 400 * 20 = 8000 J = 8 kJ
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