Question on: JAMB Physics - 1990
An object which is 3cm high is placed vertically 10cm in front of a concave mirror. If this object produces an image 40cm from the mirror, the height of the image is
A
0.75cm
B
4.00cm
C
8.00cm
D
12.00cm
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Correct Option: D
(\frac{\text {object height}}{\text{image height}}) = (\frac{\text {object distance}}{\text{image distance}})
(\frac{3}{\text{image height}}) = (\frac{10}{40})
Image height = 12cm
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