Question on: JAMB Chemistry - 2001
An elements X with relative atomic mass 16.2 contains two isotopes 168X with relative abundance of 90% and m8X with relative abundance of 10%. The value of m is
A
16
B
18
C
12
D
14
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Correct Option: B
168X, m8X
16 * (90/100) + m * (10/100) = 16.2
1440 + 10m = 1620
10m = 180
m = 18
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