Question on: JAMB Physics - 2024
An electron falls from an energy level of -5.44 eV to another level, E. If the emitted photon has wavelength 5.68 x 10-6 m, calculate the energy change. [Planck's constant = 6.63 x 10-34 Js, speed of light = 3.0 x 108 m/s]
A
1.49 x 10-20 J
B
1.49 x 10-19 J
C
3.49 x 10-20 J
D
3.49 x 10-19 J
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Correct Option: C
Here's how to solve this problem:
- Photon energy formula: E = hc / λ, where h = 6.63 x 10-34 Js, c = 3.0 x 108 m/s, λ = 5.68 x 10-6 m.
- Plug in values: E = (6.63 x 10-34 x 3.0 x 108) / 5.68 x 10-6
- Calculate: E ≈ 3.5 x 10-20 J
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