Question on: JAMB Physics - 2024
A wheelbarrow inclined at 60º to the horizontal is pushed with a force of 150 N. What is the horizontal component of the applied force?
A
130 N
B
75 N
C
60 N
D
50 N
Ask EduPadi AI for a detailed answer
Correct Option: B
To find the horizontal component of the force, we use the cosine function since the angle is with respect to the horizontal.
- Identify the given:
- Force (F) = 150 N
- Angle (θ) = 60°
- Formula:
- Horizontal component (Fx) = F * cos(θ)
- Calculation:
- Fx = 150 N * cos(60°)
- Fx = 150 N * 0.5
- Fx = 75 N
Therefore, the horizontal component of the applied force is 75 N.
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