Question on: JAMB Physics - 2020
A substance has half of 3 min. After 6 min, the count rate was observed to be 400. What was its count rate at zero time?
A
1600
B
1200
C
200
D
2400
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Correct Option: A
Let N = count rate at zero time
N \(\frac{3 min}{\to}\) \(\frac{N}{2}\) \(\frac{3 min}{\to}\) \(\frac{N}{4}\)
\(\frac{N}{4}\)
= 400
N = \(\frac{400}{N/4}\) x N
N = 1600
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