Question on: JAMB Physics - 1992
A stone, Q is thrown with velocity U at an angle of 75o to the horizontal. Another stone R is thrown with the same velocity U but with an angle of 15o to the horizontal. The ranges covered by the stones will be
A
greater for Q
B
greater for R
C
the same for Q and R
D
greater for the heavier of the two stones
Ask EduPadi AI for a detailed answer
Correct Option: C
Range = (\frac{U^2sin2\theta}{g})
RangeQ = (\frac{U^2sin150}{g})
RangeR = (\frac{U^2sin30}{g})
Since, sin30o = sin150o
therefore, RQ = RR
Add your answer
Please share this, thanks!
No responses