Question on: JAMB Physics - 2000

To solve this problem, we'll use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Given: Mass(m) = 10 kg Initial velocity (u) = 0 m/s (starting from rest) Final velocity (v) = 4 m/s Time (t) = 8 s Acceleration due to gravity (g) = 10 m/s² First, we'll find the acceleration (a) of the mass using the formula: a=(v-u)/t=4−0/8 a= 1/2=0.5m/s Now, we'll find the tension (T) in the rope using Newton's second law: T−mg=ma Substituting the given values: � − ( 10   kg × 10   m/s 2 ) = ( 10   kg × 0.5   m/s 2 ) T−(10kg×10m/s 2 )=(10kg×0.5m/s 2 ) � − 100   N = 5   N T−100N=5N � = 5   N + 100   N T=5N+100N � = 105   N T=105N So, the tension in the rope is 105   N 105N.