Question on: SS2 Physics - Electricity and Magnetism
A parallel plate capacitor has a capacitance of 12 μF. If a potential difference of 24 V is applied across the plates, what is the charge stored on the capacitor?
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The charge stored on a capacitor can be calculated using the formula:
Q = C x V, where Q is the charge, C is the capacitance, and V is the potential difference.
Plugging in the values, we have:
Q = 12 x 10-6 F x 24 V
Q = 2.88 x 10-4 C
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