Question on: JAMB Physics - 2024
A mass of gas at 40 mmHg is heated from 298 K to 348 K at constant volume. Calculate the pressure exerted by the gas.
A
50.21 mmHg
B
46.71 mmHg
C
42.35 mmHg
D
35.12 mmHg
Ask EduPadi AI for a detailed answer
Correct Option: B
Here's how to solve the problem using Gay-Lussac's Law (pressure-temperature relationship) for a constant volume:
- Identify the Knowns:
- Initial pressure, P₁ = 40 mmHg
- Initial temperature, T₁ = 298 K
- Final temperature, T₂ = 348 K
- Identify the Unknown:
- Final pressure, P₂ = ?
- Apply Gay-Lussac's Law:
- The formula is: P₁/T₁ = P₂/T₂
- Solve for P₂:
- P₂ = (P₁ * T₂) / T₁
- P₂ = (40 mmHg * 348 K) / 298 K
- P₂ ≈ 46.71 mmHg
Add your answer
Please share this, thanks!
No responses