Question on: JAMB Physics - 2020
A machine gun with a mass of 5kg fires a 50g bullet at a speed of 100 ms\(^{-1}\). The recoil speed of the machine gun is
A
0.5 ms\(^{-1}\)
B
1.5 ms\(^{-1}\)
C
1 ms\(^{-1}\)
D
2ms\(^-1\)
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Correct Option: C
Here's how to solve this problem using the principle of conservation of momentum:
* **Identify the knowns:**
* Mass of the machine gun, *M* = 5 kg
* Mass of the bullet, *m* = 50 g = 0.05 kg (convert to kg)
* Velocity of the bullet, *v* = 100 m/s
* Recoil speed of the machine gun, *V* = ?
* **Apply the conservation of momentum:** The total momentum before firing equals the total momentum after firing. Initially, both the gun and the bullet are at rest, so the initial momentum is zero.
* Initial momentum = 0
* Final momentum = *M* \* *V* + *m* \* *v*
Therefore: 0 = *M* \* *V* + *m* \* *v*
* **Solve for the recoil velocity (V):**
* *M* \* *V* = - *m* \* *v*
* *V* = - (*m* \* *v*) / *M*
* *V* = - (0.05 kg \* 100 m/s) / 5 kg
* *V* = - 5 kg m/s / 5 kg
* *V* = -1 m/s
* The negative sign indicates that the machine gun recoils in the opposite direction to the bullet's motion. The magnitude of the recoil speed is 1 m/s.
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