A cell whose internal resistance is 0 55 Omega ... - JAMB Physics 2022 Question
A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an external resistor. What is the lost voltage of the cell?
A
4.00 V
B
2.20 V
C
0.15 V
D
8.00 V
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Correct Option: B
The lost voltage (V_lost) in a cell is calculated using the formula:
V_lost = I * r
where:
- I is the current flowing through the cell.
- r is the internal resistance of the cell.
Given:
- I = 4 A
- r = 0.55 Ω
Therefore, V_lost = 4 A * 0.55 Ω = 2.20 V
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