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A cell whose internal resistance is 0 55 Omega ... - JAMB Physics 2022 Question

A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an external resistor. What is the lost voltage of the cell?

A

4.00 V

B

2.20 V

C

0.15 V

D

8.00 V

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Correct Option: B

The lost voltage (V_lost) in a cell is calculated using the formula:

V_lost = I * r

where:

  • I is the current flowing through the cell.
  • r is the internal resistance of the cell.

Given:

  • I = 4 A
  • r = 0.55 Ω

Therefore, V_lost = 4 A * 0.55 Ω = 2.20 V

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