Question on: WAEC Physics - 2012
A block of wood of density 0.6 gcm-3, weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm-3. Calculate volume of the portion immersed (g = 10ms-2)
A
510cm3
B
340cm3
C
254cm3
D
170cm3
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Correct Option: B
V = (\frac{M}{D})
= (\frac{3.06}{10} \times \frac{1000}{0.9} = 340)
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