Question on: WAEC Physics - 2009
A battery of e.m.f. 12.0V and internal resistance0.5(\Omega) is connected to 1.5(\Omega) and 4.0(\Omega) series resistor. Calculate the terminal voltage of the battery.
A
13.0V
B
11.0V
C
3.0V
D
1.0V
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Correct Option: B
(\frac{V}{R} = \frac{E}{R + r} = \frac{V}{5.5} = \frac{12}{6})
v = 11.0V
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