Question on: SS2 Mathematics - Probability
\(A = \{ a,e,i,o,u\}\) and \(B = \{ p,h,f,v,m,w\}\). Find the probability of choosing a letter from the English alphabet which is either in event \(A\) or \(B\).
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A
\(\frac{5}{26}\)
B
\(\frac{5}{13}\)
C
\(\frac{1}{5}\)
D
\(\frac{13}{26}\)
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Correct Option: B
\[total\ number\ of\ english\ alphabets = 26\]
\[P(A) = \frac{5}{26}\]
\[P(B) = \frac{5}{26}\]
\(P(A\ or\ B) = P(A \cup B) = P(A) + P(B) = \ \frac{5}{26} + \frac{5}{26} = \frac{10}{26} = \frac{5}{13}\)
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