1997 - JAMB Mathematics Past Questions and Answers - page 1

(64.764 - 35.236)(64.764 + 35.236)

= 29.528 x 100

= 2950 to 3 sig. fig.

(0.006)³ + (0.004)³ = 2.16 x 10^-7

(2.16 + 0.64) x 10^-7

= 2.8 x 10^-7

log_a 13.5 = log_a \(\frac{27}{2}\)

= 3log_a 3 - log²_a

= 3 x 1.097 - 0.693

= 2.598

\(\frac{(2\sqrt{3} + 3\sqrt{5})(3\sqrt{5} + 2\sqrt{3})}{(3\sqrt{5} - 2\sqrt{3})(3\sqrt{5} - 2\sqrt{3})}\)

= \(\frac{5 + 12\sqrt{15}}{33}\)

=\(\frac{19 + 4\sqrt{15}}{11}\)

1 = \(\frac{PRT}{100}\)

1 = 1240 - 1000

= 240

R = \(\frac{240 \times 100}{100 \times 3}\)%

= 8%

x + 1 = 0, x = -1; f(x) = x³ + 2x² + qx - 6

0 = -1 + 2 - q - 6

q = -5

\(\frac{2}{x} - {\frac{2}{x}}\) = 2.....(1)

\(\frac{4}{x} + {\frac{3}{y}}\) = 10

\(\frac{6}{x}\) = 12 \(\to\) x = \(\frac{6}{12}\)

x = \(\frac{1}{2}\)

put x = \(\frac{1}{2}\) in equation (i)

= 4 - \(\frac{3}{y}\) = 2

= 4 - 2

= \(\frac{3}{y}\)

therefore y = \(\frac{3}{2}\)